GMAT Practice Test 2025 – Comprehensive All-in-One Guide for Success!

Question: 1 / 400

For the product of k consecutive integers, which of the following is true?

It is always greater than k

The product of \( k \) consecutive integers, denoted as \( n \times (n+1) \times (n+2) \times \ldots \times (n+k-1) \), will always yield a value greater than \( k \) when \( n \) begins at 1 or any positive integer. This is because the smallest product occurs starting from the first positive integer (1), where the product of, for example, 3 consecutive integers is \( 1 \times 2 \times 3 = 6 \), which is greater than 3.

As \( n \) increases, the product increases even more significantly, especially as \( k \) grows larger than 2. The nature of consecutive integers, encompassing both minimum and maximum values within and extending beyond \( n \), generally ensures that the product accelerates beyond just \( k \).

In cases where \( n \) starts from zero or is negative, the product may still exceed \( k \) in absolute value. For instance, if \( n = -1 \) and \( k = 2 \), the integers would be \( -1 \) and \( 0 \), resulting in a product of \(

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It may be less than k

It is generally not related to k

It can be equal to k

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